Решите пожалуйста!!!!

Решите задачу:

$(x + 1)(x + 2) = {x}^{2} + 2x + x + 2 = {x}^{2} + 3x + 2 \\ \\ (x - 1)(x - 2) = {x}^{2} - 2x - x + 2 = {x}^{2} - 3x + 2 \\ \\ (x + 1)(x - 3) = {x}^{2} - 3x + x - 3 = {x}^{2} - 2x - 3 \\ \\ (x + 2)(x - 3) = {x}^{2} - 3x + 2x - 6 = {x}^{2} - x - 6 \\ \\ (2x - 1)(x + 2) =2 {x}^{2} + 4x - x - 2 = 2 {x}^{2} + 3x - 2 \\ \\ (x - 3)(3x + 2) = 3 {x}^{2} + 2x - 9x - 6 = 3 {x}^{2} - 7x - 6 \\ \\ (5x + 1)(5x - 1) = (5x) {}^{2} - {1}^{2} = 25 {x}^{2} - 1 \\ \\ (3x - 2)(3x + 2) = (3x) {}^{2} - {2}^{2} = 9 {x}^{2} - 4$