Даю много баллов кто первый ответит

Решите задачу:

$1) {x}^{4} - 0,49 {y}^{2} = {x}^{4} - \frac{49}{100} {y}^{2} = ( {x}^{2} - \frac{7}{10} y)( {x}^{2} + \frac{7}{10} y)$
$2) \: - 0 ,64 {z}^{2} + {t}^{6} = - \frac{64}{100} {z}^{2} + {t}^{6} = {t}^{6} - \frac{16}{25} {z }^{2} = ( {t}^{3} - \frac{4}{5} z)( {t}^{3} + \frac{4}{5} z)$
$3) \: 0,81 {a}^{8} - {b}^{2} = \frac{81}{100} {a}^{8} - {b}^{2} = ( \frac{9}{10} {a}^{4} - b)( \frac{9}{10} {a}^{4} + b)$
$4) \: \frac{361}{400} {m}^{2} - {n}^{10} =( \frac{19}{20} m - {n}^{5} )( \frac{19}{20} m + {n}^{5} )$
$5) {c}^{6} - \frac{289}{324} {d}^{4} = ({c}^{3} - \frac{17}{18} {d}^{2})({c}^{3} + \frac{17}{18} {d}^{2})$
$6) 5,76 {x}^{12} - \frac{4}{81} {y}^{8} = (2,4 {x}^{6} - \frac{2}{9} {y}^{4} )(2,4 {x}^{6} + \frac{2}{9} {y}^{4} )$