Сделайте срочно уравнения 1) (х-7)^2+3=(x-2) (x+2) 2) (2x+3)^2-(7-2x)^2=2 3)...

Объяснение: sqrt() - Квадратный корень

1) (х-7)^2+3=(x-2) (x+2)

(x-7)^2 = x^2 - 4 - 3

(x-7)^2 = x^2 - 7

x^2 = (x-7)^2 + 7

x^2 = x^2 - 14x + 49 + 7

x^2 = x^2 - 14x + 56

x^2 - x^2 = -14x +56

-14x + 56 = 0

-14(x - 4) = 0

x - 4 = 0

x = 4

2) (2x+3)^2-(7-2x)^2=2

(2x+3-7+2x)(2x+3+7-2x) = 2

10(4x-4) = 2

4x - 4 = $\frac{2}{10}$

4(x-1) = $\frac{2}{10}$

x-1 = $\frac{1}{20}$

x = $\frac{1}{20} +1$

x = $\frac{21}{20}$

3) (2-x)^2-x(x+1.5)=4

$4 - 4x + x^{2} - (x^{2}+1.5x ) = 4$

$4 - 4x + x^{2} - x^{2} -1.5x=4$

$4 - 5.5x = 4$

$-5.5x=0$

$x=0$