1) (х-2)/(2х -4) = (х-2)/2(х-2) = 1/2
2)log√2(1/2) ≤ log√2 (x+1)/(x +2), √2>1, ⇒
⇒ 1/2 ≤ (х+1)/(х+2) (x +2 -2x -2)/(2(x+2)) ≤0 -x/2(х+2) ≤ 0
(х+1)/(х+2) > 0 нули -1 и -2 -∞ + -2 - -1 + +∞
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x -2> 0, ⇒ х > 2, ⇒
Ищем решение:
-∞ - -2 + -1 + 0 - 2 - -∞
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Ответ: (2;+∞)