(4−1)⋅(4+1)⋅(4^2+1)⋅(4^4+1)⋅(4^8+1)−4^16+48

Question

(4−1)⋅(4+1)⋅(4^2+1)⋅(4^4+1)⋅(4^8+1)−4^16+48

Answer 1

Ответ:

Объяснение:

(4−1)⋅(4+1)⋅(4^2+1)⋅(4^4+1)⋅(4^8+1)−4^16+48=(4^2−1)⋅(4^2+1)⋅(4^4+1)⋅(4^8+1)−4^16+48=(4^4−1)⋅(4^4+1)⋅(4^8+1)−4^16+48=

(4^8−1)⋅(4^8+1)−4^16+48=4^16−1−4^16+48=-1+48=47