Решение
x" alt="\sqrt{x+2}>x" align="absmiddle" class="latex-formula">
x,x\geq0" alt="\sqrt{x+2}>x,x\geq0" align="absmiddle" class="latex-formula">
x ∈⟨-1 , 2 ⟩ , х≥0
х∈[0,2⟩
x ,x<0" alt="\sqrt{x+2}>x ,x<0" align="absmiddle" class="latex-formula">
х∈R , х<0</p>
х∈⟨-∞ , 0 ⟩
х∈⟨-∞,2⟩ , х≥-2
Ответ
х∈[ -2,2⟩