Уравнение решить​

Решите задачу:

$\frac{x - 3}{x + 3} = \frac{4(x + 3}{x - 3}$

$\frac{(x - 3)(x - 3)(x + 3)}{x +3} = \frac{4(x + 3)(x + 3)(x - 3)}{ x - 3}$

${(x - 3)}^{2} = 4 {(x + 3)}^{2}$

${x}^{2} - 6x + 9 = 4( {x}^{2} + 6x + 9)$

${x}^{2} - 6x + 9 = 4 {x}^{2} + 24x + 36$

$- 3 {x}^{2} - 30x - 27 = 0$

${x}^{2} + 10x + 9 = 0$

$x1 + x2 = - p$

$x1 \times x2 = q$

$x1 = - 9$

$x2 = - 1$

$OTBET: - 9; - 1.$

Уравнение решить