+oo\ n^4-100n^2-100\\
n^4-100n^2-100
n^4(1-\frac{100}{n^2}-\frac{100}{n^4})\\
+oo*1=+oo" alt="lim \ n->+oo\ n^4-100n^2-100\\
n^4-100n^2-100
n^4(1-\frac{100}{n^2}-\frac{100}{n^4})\\
+oo*1=+oo" align="absmiddle" class="latex-formula">
Ответ + бесконечность
+oo\ \frac{n+12}{n+11}\\
1+\frac{1}{n+11}\\
1+0=1\\
\\
lim \ n->+oo\ \frac{3n}{n+2}\\
\frac{3}{1+\frac{2}{n}}=3
" alt="lim \ n->+oo\ \frac{n+12}{n+11}\\
1+\frac{1}{n+11}\\
1+0=1\\
\\
lim \ n->+oo\ \frac{3n}{n+2}\\
\frac{3}{1+\frac{2}{n}}=3
" align="absmiddle" class="latex-formula">