Помогите пожалуйста! !!

1. $\frac{(5x-3)*(5x+3)}{x(x+4)-3(x+4)}$ * $\frac{x+4}{5x+3}- \frac{2x}{x-3}$ = $\frac{5x-3}{(x+4)(x-3)}*(x+4)- \frac{2x}{x-3}$ = $\frac{5x-3}{x-3}-\frac{2x}{x-3} = \frac{5x-3-2x}{x-3}$ = $\frac{3x-3}{x-3}$

2. ....= $(\frac{2}{x-2}+\frac{3x-4}{(x+3)*(x-2)} *\frac{2x}{x+3} ) *\frac{x}{2x-5}$ = $\frac{2(x+3)+3x-4+2x*(x-2)}{(X+3)(x-2)}* \frac{x}{2x-5}$ = $\frac{2x+6+3x-4+2x^{2}-4 }{(x+3)(x-2)}*\frac{x}{2x-5} =[tex]\frac{x+2+2x^{2} }{(x+3)(x-2)}*\frac{x}{2x-5}$ = $\frac{x(x+2+2x^{2}) }{(x+3)(x-2)(2x-5)}$ = $\frac{x^{2}+2x+2x^{3} }{(x^{2}-2x+3x-6)*(2x-5)}$ = $\frac{2x^{3}+x^{2}+2x }{2x^{3}-3x^{2}-17x+30 }$