Помогите пожалуйста с заданиями на фото.Срочно

x = 10 - y\\ xy = 24 \\ y(10 - y) = 24 \\ - {y}^{2} + 10y - 24 = 0 \\ {y}^{2} - 10y + 24 = 0 \\ y1 + y2 = 10 \\ y1 \times y2 = 24 \\ y1 = 6 \\ y2 = 4" alt="x + y = 10 = > x = 10 - y\\ xy = 24 \\ y(10 - y) = 24 \\ - {y}^{2} + 10y - 24 = 0 \\ {y}^{2} - 10y + 24 = 0 \\ y1 + y2 = 10 \\ y1 \times y2 = 24 \\ y1 = 6 \\ y2 = 4" align="absmiddle" class="latex-formula">

$x1 = 10 - 6 = 4 \\ x2 = 10 - 4 = 6$

ответ: (6;4) или (4;6)

${( {x}^{2} - 2x})^{2} - 3( {x}^{2} - 2x) - 4 = 0 \\ y = {x}^{2} - 2x \\ {y}^{2} - 3y - 4 = 0 \\ y1 + y2 = 3 \\ y1 \times y2 = - 4 \\ y1 = 4 \\ y2 = - 1$