0\; \; \to \; \; x^2-5x+16<0\\\\D=\underline {-39<0}\; \; \to \; \; x^2-5x+16>0\; \; \to \; \; otvet:\; x\in \varnothing \\\\2)\; \; x^2-4\geq 0\; \; \to \; \; (x-2)(x+2)\geq 0\\\\+++[-2\, ]---[\, 2\, ]+++\\\\x\in (-\infty ,-2\, ]\cup [\, 2,+\infty )\\\\3)\; \; (x+6)(x+3)(x-6)(x-9)\geq 0\\\\+++[-6]---[-3]+++[\, 6\, ]---[\, 9\, ]+++\\\\x\in (-\infty ,-6\, ]\cup [-3,6\, ]\cup [\, 9,+\infty )\\\\4)\; \; (x-2)^2(x^2-9)\leq 0\; \; \to \; \; (x-2)^2(x-3)(x+3)\leq 0\\\\+++[-3\, ]---[\, 2\, ]---[\, 3\, ]+++" alt="1)\; \; -x^2+5x-16>0\; \; \to \; \; x^2-5x+16<0\\\\D=\underline {-39<0}\; \; \to \; \; x^2-5x+16>0\; \; \to \; \; otvet:\; x\in \varnothing \\\\2)\; \; x^2-4\geq 0\; \; \to \; \; (x-2)(x+2)\geq 0\\\\+++[-2\, ]---[\, 2\, ]+++\\\\x\in (-\infty ,-2\, ]\cup [\, 2,+\infty )\\\\3)\; \; (x+6)(x+3)(x-6)(x-9)\geq 0\\\\+++[-6]---[-3]+++[\, 6\, ]---[\, 9\, ]+++\\\\x\in (-\infty ,-6\, ]\cup [-3,6\, ]\cup [\, 9,+\infty )\\\\4)\; \; (x-2)^2(x^2-9)\leq 0\; \; \to \; \; (x-2)^2(x-3)(x+3)\leq 0\\\\+++[-3\, ]---[\, 2\, ]---[\, 3\, ]+++" align="absmiddle" class="latex-formula">