Номер 1,под буквой б уравнение

$\frac{2}{9}(0,45-2,7y) -\frac{2}{17}(0,51-3,4y) = 0,16\\\\\frac{2}{9}(\frac{9}{20} - \frac{27}{10}y) - \frac{2}{17}(\frac{51}{100} - \frac{17}{5}y) = 0,16\\\\\frac{1}{10} - \frac{3}{5}y - \frac{3}{50} + \frac{2}{5}y = \frac{16}{100}\\\\\frac{5}{50} - \frac{3}{5}y - \frac{3}{50} + \frac{2}{5}y = \frac{16}{100}\\\\\frac{2}{50} - \frac{3}{5}y + \frac{2}{5}y = \frac{16}{100}\\\\\frac{1}{25} - \frac{1}{5}y = \frac{16}{100}\\\\\frac{1}{25} - \frac{1}{5}y = \frac{4}{25}$

$-\frac{1}{5}y = \frac{4}{25} - \frac{1}{25}\\\\-\frac{1}{5}y = \frac{3}{25}\\\\y = -\frac{5*3}{25}\\\\y = -\frac{3}{5}\\y = -0,6$

Ответ: -0,6