1) у' = 16x³ -15[² +4x
y' = (3(3x +1) - 3(3x -1))/(3x +1)² = (9x +3 -9x +3)/(3x +1)² = 6/(3x +1)²
y' = 1/2√(x⁵ -4x³ -4) *(x⁵ -4x³ -4)' = (5x⁴ -12x²)/2√(x⁵ -4x³ -4)
4) ∫3dx/Cos²(3x -1)= 3*1/3*tg(3x -1) + C = tg(3x -1) + C
5) S = ₀∫¹ x³dx = x⁴/4 |₀¹ = 1/4