Объяснение:
2sin(√x + π/2) = √3,
sin (√x + π/2 ) =√3 / 2,
√x + π/2 = (-1)ⁿ(π/3) + πn, n∈Z
1)
√x + π/2 = (π/3) + 2πn,
√x = (π/3 - π/2) + 2πn,
√x = (2π/6 - 3π/6) + 2πn,
√x = (-π/6) + 2πn n = 1,2,3,....
x = π²(-1/6 + 2n )² n=1,2,3,....
2)
√x + π/2 = π - (π/3) + 2πk,
√x = π - π/2- (π/3) + 2πk,
√x = π/6 + 2πk k=1,2,3,....
x = π²(1/6 + 2k)² k=1,2,3,...