Пожалуйста, подробно, по действиям)

Question 1

Question 2

Решите задачу:

$1)\; \; \Big (3\frac{1}{3}+2,5\Big ):\Big (3\frac{1}{3} -2,5\Big )=\Big (\frac{10}{3}+\frac{5}{2}\Big ):\Big (\frac{10}{3}-\frac{5}{2}\Big )=\frac{35}{6}:\frac{5}{6}=\frac{35}{5}=7\\\\40\%\; \; ot\; \; 7=7\cdot 0,4=2,8$

$2)\; \; \frac{3\frac{1}{3}\, :\, 10+0,175\, :\, 0,35}{1,75-1\frac{11}{17}\, \cdot \, \frac{51}{56}}=\frac{\frac{10}{3\, \cdot \, 10}\, +\frac{175}{350}}{\frac{7}{4}\, -\frac{28}{17}\, \cdot \, \frac{51}{56}}=\frac{\frac{1}{3}\, +\, \frac{1}{2}}{\frac{7}{4}\, -\frac{3}{2}}=\frac{\frac{5}{6}}{\frac{1}{4}}=\frac{5\, \cdot \, 4}{6\, \cdot 1}=\frac{10}{3}=3\frac{1}{3}\\\\54\%\; \; ot\; \; \frac{10}{3}=\frac{10}{3}\cdot 0,54=\frac{10}{3}\cdot \frac{54}{100}=\frac{18}{10}=1,8$

Question 3

Пошаговое объяснение:

$\tt\displaystyle(3\frac{1}{3}+2,5):(3\frac{1}{3}-2,5)=7\\\\1) (3\frac{1}{3}+2,5)= (3\frac{1}{3}+2\frac{5}{10})=(3\frac{1}{3}+2\frac{1}{2})=5+(\frac{1}{3}+\frac{1}{2})= 5+(\frac{2}{6}+\frac{3}{6})=5\frac{5}{6}\\\\2) (3\frac{1}{3}-2,5)= (3\frac{1}{3}-2\frac{5}{10})=1+(\frac{1}{3}-\frac{5}{10})=1+(\frac{1}{3}-\frac{1}{2})=1+(\frac{2}{6}-\frac{3}{6})=1-\frac{1}{6}=\frac{5}{6}\\\\3)5\frac{5}{6}:\frac{5}{6}=\frac{35}{6}*\frac{6}{5}=7$

Найдем 40% от значения:

$\tt\displaystyle 7*40:100=\frac{14}{5}=2,8$

$\tt\displaystyle\frac{3\frac{1}{3}:10+0,175:0,35}{1,75-1\frac{11}{17}*\frac{51}{56}}=1,8\\\\\\1)3\frac{1}{3}:10=\frac{10}{3}*\frac{1}{10}=\frac{1}{3}\\\\2)0,175:0,35=\frac{1}{2}=0,5\\\\3)\frac{1}{3}+\frac{1}{2}=\frac{2}{6}+\frac{3}{6}=\frac{5}{6}\\\\4)1\frac{11}{17}*\frac{51}{56}=\frac{28}{17}*\frac{51}{56}=\frac{1}{1}*\frac{3}{2}=\frac{3}{2}=1,5\\\\5)1,75-1,5=0,25=\frac{1}{4}\\\\6)\frac{5}{6}:\frac{1}{4}=\frac{5}{6}*4=\frac{20}{6}=\frac{10}{3}$

Найдем 54% от значения:

$\tt\displaystyle\frac{10}{3}*54:100=\frac{9}{5}=1,8$