2x4-5x2+2=0 памагити пж...

$2x^{4}-5x^{2}+2=0\\ x^{2}=t\\2t^{2}-5t+2=0$

$D=(-5)^{2}-4*2*2=25-16=9=3^{2}$

$t1=\frac{5+3}{2*2}=\frac{8}{4}=2\\\\t2=\frac{5-3}{2*2}=\frac{2}{4}=0,5$

0\\x^{2}=2 \\x^{2} =\frac{1}{2} \\" alt="x^{2}=t \\t>0\\x^{2}=2 \\x^{2} =\frac{1}{2} \\" align="absmiddle" class="latex-formula">

Ответ: $\sqrt{2}, -\sqrt{2}, \sqrt{\frac{2}{2}}, -\sqrt{\frac{2}{2}}$

2x4-5x2+2=0 памагити пж...​