Помогите пожалуйста 40 баллов1) 3√2(5√2-√32) = (4-5√2) = (√7 - 2√3)(√7 + 2√3) = 2) √300...

Решите задачу:

$1) 3\sqrt{2}(5\sqrt{2}- \sqrt{32})=15*2-3 \sqrt{32*2}=30-24=6 \\ (4-5 \sqrt{2})^{2}=16-40 \sqrt{2}+50=66-40 \sqrt{2} \\ ( \sqrt{7}-2\sqrt{3})( \sqrt{7}+2\sqrt{3})=7-12=-5$
$2) \frac{1}{5} \sqrt{300}-4 \sqrt{ \frac{3}{16}}- \sqrt{75}=\frac{1}{5}*10\sqrt{3}-\sqrt{ \frac{3}{16}*16}- \sqrt{5^{2}*3}= \\ =2\sqrt{3}-\sqrt{3}-5\sqrt{3}=-4 \sqrt{3} \\ (3\sqrt{2}-1)(\sqrt{8}+2)=(3\sqrt{2}-1)(2\sqrt{2}+2)=6*2-2\sqrt{2}+6\sqrt{2}-2= \\ =10+4\sqrt{2} \\ ( \sqrt{5}+2 )^{2}-(3- \sqrt{5})^{2}=5+4\sqrt{5}+4-9+12\sqrt{5}-5=16\sqrt{5}-5$