0\\\\\\x_1=3\; ,\; \; x_2=4\; ,\; \; x_3=-7\\\\znaki:\; \; \; ---(-7)+++(3)---(4)+++\\\\x\in (-7;3\, )\cup (\; 4;+\infty \, )" alt="\dfrac{(x-3)(x-4)}{x+7}>0\\\\\\x_1=3\; ,\; \; x_2=4\; ,\; \; x_3=-7\\\\znaki:\; \; \; ---(-7)+++(3)---(4)+++\\\\x\in (-7;3\, )\cup (\; 4;+\infty \, )" align="absmiddle" class="latex-formula">