Помогите,пожалуйста!
Відповідь:
a) sin(2/3π) = √3/2
cos(2/3π) = - 1/2
tg(2/3π) = -√3
ctg(2/3π) = -√3/3
б)sin(3/4π) = √2/2
cos(3/4π) = - √2/2
tg(3/4π) = -1
ctg(3/4π)= -1
в)sin(5/6π) = 1/2
cos(5/6π) = -√3/2
tg(5/6π) = -√3/3
ctg(5/6π) = -√3