((x^2-6)/x)^2 -5=4*((x^2-6)/x)

Ответ:

$x_{1} =7\\x_{2.4} =-2\\x_{3}=3$

Объяснение:

$(\frac{x^{2} -6}{x} )^{2} -5 = 4* \frac{x^{2} -6}{x}\\(\frac{x^{2} -6}{x})^{2} -4*\frac{x^{2} -6}{x}-5=0\\\frac{x^{2} -6}{x} = z\\z^{2} -4z-5=0\\\sqrt{D} = \sqrt{(-4)^{2} -4*1*(5)} = \sqrt{16+20} =\sqrt{36} = 6\\ z_{1}= \frac{4+6}{2} = 5\\z_{2} = \frac{4-6}{2} = -1\\1) \frac{x^{2} -6}{x} = 5\\x^{2} -6=5x\\x^{2} -5x-6=0\\\sqrt{D} =\sqrt{ (-5)^{2} - 4*1*(-6) } = \sqrt{25+24}=\sqrt{49} = 9\\x_{1} = \frac{5+9}{2*1} = 7\\x_{2} =\frac{5-9}{2} = -2\\2) \frac{x^{2} -6}{x} =-1\\x^{2} -6 = -x$ $x^{2} +x-6=0\\\sqrt{D}=\sqrt{1^{2}-4*1*(-6) } = \sqrt{25} =5\\x_{3} =\frac{1+5}{2}=3\\x_{4} =\frac{1-5}{2} =-2\\$