Помогите срочно плиз!​

0 голосов
20 просмотров

Помогите срочно плиз!​


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Алгебра (21 баллов) | 20 просмотров
Дан 1 ответ
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\\ \\ \frac{12x - 7}{15x} + \frac{3x - 2}{15x} = \frac{12x - 7 + 3x - 2}{15x} = \frac{15x - 9}{15x} = \frac{3(5x - 3)}{15x} = \frac{5x - 3}{5x} \\ \frac{ax + ay}{x {y}^{2} } \times \frac{ {x}^{2}y }{3x + 3y} = \frac{a(x + y) \times x {}^{2} y}{x {y}^{2} \times 3(x + y)} = \frac{ax}{3y} " alt="\frac{15a(a - b)}{40b(a - b)} = \frac{3a}{8b} \\ \frac{y {}^{2} + y}{ {y}^{2} } = \frac{y(y + 1)}{ {y}^{2} } = \frac{y + 1}{y}

\\ \\ \frac{12x - 7}{15x} + \frac{3x - 2}{15x} = \frac{12x - 7 + 3x - 2}{15x} = \frac{15x - 9}{15x} = \frac{3(5x - 3)}{15x} = \frac{5x - 3}{5x} \\ \frac{ax + ay}{x {y}^{2} } \times \frac{ {x}^{2}y }{3x + 3y} = \frac{a(x + y) \times x {}^{2} y}{x {y}^{2} \times 3(x + y)} = \frac{ax}{3y} " align="absmiddle" class="latex-formula">

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