Решите пожалуйста 771 1

Решите задачу:

$( \frac{0.3 \times (3.6 - 2.8)}{0.25 \times (0.94 + 1.06)} + \frac{(0.2 - 0.15) \div 0.001}{(4.7 - 3.9) \times 10} ) \div 26.92 = 0.25 \\ \\ \frac{0.3 \times (3.6 - 2.8)}{0.25 \times (0.94 + 1.06)} = \frac{0.3 \times 0.8}{0.25 \times 2} = \frac{0.3 \times 0.4}{0.25} = \frac{0.12}{0.25} = \frac{12}{25} = 0.48 \\ \frac{(0.2 - 0.15) \div 0.001}{(4.7 - 3.9) \times 10} = \frac{0.05 \div 0.001}{0.8 \times 10} = \frac{50}{8} = \frac{25}{4} = 6.25 \\ 0.48 + 6.25 = 6.73 \\ 6.73 \div 26 . 92 = \frac{1}{4} = 0.25$