1\ \ ne\ podxodit\ \ ,\ \ t_1=\dfrac{-11+19}{10}=\dfrac{4}{5}=0,8\\\\sinx=0,8\\\\x=(-1)^{n}\cdot arcsin0,8+\pi n=\left[\begin{array}{l}arcsin0,8+2\pi n\ ,\ n\in Z\\\pi -arcsin0,8+2\pi n\ ,\ n\in Z\end{array}\right" alt="5sin^2x+11sinx=12\\\\t=sinx\ ,\ \ -1\leq t\leq 1\ \ ,\ \ \ 5t^2+11t-12=0\ \ ,\ \ D=361=19^2\ ,\\\\t_1=\dfrac{-11-19}{10}=3>1\ \ ne\ podxodit\ \ ,\ \ t_1=\dfrac{-11+19}{10}=\dfrac{4}{5}=0,8\\\\sinx=0,8\\\\x=(-1)^{n}\cdot arcsin0,8+\pi n=\left[\begin{array}{l}arcsin0,8+2\pi n\ ,\ n\in Z\\\pi -arcsin0,8+2\pi n\ ,\ n\in Z\end{array}\right" align="absmiddle" class="latex-formula">
Ответ: №1 и №3 .