Ответ:
0\end{array}\right\ \ \left\{\begin{array}{ccc}(x-1)(x-5)\leq 0\\(x-3)(x-5)>0\end{array}\right\\\\\\\left\{\begin{array}{l}x\in [\, 1\, ;\, 5\ ]\\x\in (-\infty ;3)\cup (5;+\infty )\end{array}\right\ \ \ \Rightarrow \ \ \ x\in [\ 1\, ;\, 3\, )" alt="\left\{\begin{array}{l}x^2-6x+5\leq 0\\\dfrac{4\sqrt3-7}{x^2-8x+15}\leq 0 \end{array}\right\ \ \left\{\begin{array}{ccc}x^2-6x+5\leq 0\\x^2-8x+15>0\end{array}\right\ \ \left\{\begin{array}{ccc}(x-1)(x-5)\leq 0\\(x-3)(x-5)>0\end{array}\right\\\\\\\left\{\begin{array}{l}x\in [\, 1\, ;\, 5\ ]\\x\in (-\infty ;3)\cup (5;+\infty )\end{array}\right\ \ \ \Rightarrow \ \ \ x\in [\ 1\, ;\, 3\, )" align="absmiddle" class="latex-formula">