Помогите пожалуйста

Ответ:

${x}^{3} + {x}^{2} + x + 1 = {x}^{2} (x + 1) + (x + 1) = ( {x}^{2} + 1)(x + 1)$

Объяснение:

${a}^{2} - ab - 8a + 8a = a(a - b) - 8(a - b) = (a - 8)(a - b)$

${y}^{5} - {y}^{3} - {y}^{2} + 1 = {y}^{3} ( {y}^{2} - 1) - ( {y}^{2} - 1) = ({y}^{3} - 1)( {y}^{2} - 1)$

$ab - 5b + {b}^{2} - 5a = ab + {b}^{2} - 5b - 5a = b(a + b) - 5(a + b) = (b - 5)(a + b)$

${a}^{4} + 2 {a}^{3} - a - 2 = {a}^{3} (a + 2) - (a + 2) = ( {a}^{3} - 1)(a + 2)$

$7x - xy +7y - {x}^{2} = 7x + 7y - xy - {x}^{2} = 7(x + y) - x(y + x) = (7 - x)(x + y)$

${b}^{6} - 3 {b}^{4} - 2 {b}^{2} + 6 = {b}^{6} - 2 {b}^{2} - 3 {b}^{4} + 6 = {b}^{2} ( {b}^{4} - 2) - 3( {b}^{4} - 2) = ( {b}^{2} - 3)( {b}^{4} - 2)$

kn-nm-n^2+mk=kn-n^2-mn+mk=n (k-n)-m (n-k)=(n+m)(k-n)

Помогите пожалуйста​