СРОЧНО!!!!!!!!!!!!!!!!Решите систему неравенств:

$\left \{ {{6x-8<5x-5} \atop {- x^{2} -x-2 \geq -4x}} \right. \\\ \left \{ {{6x-5x<8-5} \atop {- x^{2} -x+4x-2 \geq 0}} \right. \\\ \left \{ {{x<3} \atop { x^{2} -3x+2 \leq 0}} \right. \\\ \left \{ {{x<3} \atop { (x-2)(x-1) \leq 0}} \right. \\\ \left \{ {{x<3} \atop { 1 \leq x \leq 2}} \right. \\\ 1 \leq x \leq 2$
Ответ: 1≤х≤2