\infty} \frac{3x-1}{x^2+7x+5}=\\\\lim_{x->\infty} \frac{\frac{3}{x}-\frac{1}{x^2}}{1+\frac{7}{x}+\frac{5}{x^2}}=\frac{0-0}{1+0+0}=0" alt="lim_{x->\infty} \frac{3x-1}{x^2+7x+5}=\\\\lim_{x->\infty} \frac{\frac{3}{x}-\frac{1}{x^2}}{1+\frac{7}{x}+\frac{5}{x^2}}=\frac{0-0}{1+0+0}=0" align="absmiddle" class="latex-formula">
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