Решить уравнение (2х^2 -4√2х+3=0)

Question

Решить уравнение (2х^2 -4√2х+3=0)

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Answer 1

D = (4V2)^2 - 4*2*3 = 32-24 = 8 = (2V2)^2
x1 = (4V2 - 2V2) / 4 = 2V2 / 4 = V2 / 2
x2 = (4V2 + 2V2) / 4 = 6V2 / 4 = 3V2 / 2