sin(x/2- π/6)+1=0

Question

sin(x/2- π/6)+1=0

Answer 1

sin(x/2- π/6)+1=0

1 = sin(π/2)

sin(x/2 - π/6) + sin(π/2) = 0

sin(x/2 - π/6) = -sin(π/2) 

sin(x/2 - π/6) = sin(-π/2)

x/2 - π/6 = (3x - π)/6

(3x - π)/6 = -π/2

3x - π + 3π = 0

3x +2π = 0

3x = -2π

x = -2π/3

Ответ: -2π/3

 

Answer 2

sin(x/2- π/6)+1=0

sin(x/2- π/6)= -1

x/2- π/6 = -π/2 + 2πn

x/2 = π/6-π/2 + 2πn

x/2 = -2π/6 + 2πn

x = -2π/3 + 4πn