Решить уравнения1)2)

$1)\\\sqrt{\frac{2x}{x^2-1}}-\frac{2}{\sqrt{x+1}}=0\\ \frac{\sqrt{2x}}{\sqrt{(x-1)(x+1)}}-\frac{2}{\sqrt{x+1}}=0\\ \frac{\sqrt{2x}-2\sqrt{x-1}}{\sqrt{x^2-1}}=0\\ \sqrt{2x}-2\sqrt{x-1}=0\\ \sqrt{2x}=2\sqrt{x-1}\\ 2x=4(x-1)\\ 2x=4x-4\\ 2x=4\\ x=2\\ 2)\\10x-\sqrt{2x+1}=1\\ \sqrt{2x+1}=10x-1\\ 2x+1=100x^2-20x+1\\ 100x^2-22x=0\\ x(100x-22)=0\\ x=0\\ x=\frac{11}{50}$
Ответ $2;\frac{11}{50}$