1) tg(2x-п/3)=-52) 4cos(x/4+п/6)=sqrt3

Question

1) tg(2x-п/3)=-5
2) 4cos(x/4+п/6)=sqrt3

Answer 1

1) 2x-pi\3=-arctg5+pi*n
x=-1\2*arctg5+pi\6+pi\2*n
2)x\4+pi\6=+-arccos(sqrt3\4)+2pi*n
x=+-4arccos(sqrt3\4)-2pi\3+8pi*n