(5cosx+4):(4tgx-3)=0

Question

(5cosx+4):(4tgx-3)=0

Answer 1

5cosx+4=0 U 4tgx-3≠0
cosx=-4/5⇒x=π-arccos0,8+2πn
tgx≠3/4⇒cos²x≠1:(1+tg²x)≠1:(1+9/16)≠16/25⇒cos≠4/5 U cosx≠-4/5
нет решения