Решите неравенство: 49-х^2/5-х <0
(49-x²)/(5-x)<0 ОДЗ: 5-x≠0 => x≠5 (49-x²)/(5-x)=0 (7+x)(7-x)/(5-x)=0 (7+x)(7-x)=0 7+x=0 => x=-7, или 7-x=0 => x=7 x₁=7 x₂=-7 - -7 + 5 - 7 + ------°------------°-----°-------- x∈(-∞;-7)∪(5;7)