Решите 7 и 8 номер пожалуйста

7. $\frac{ n^{2} (n- \sqrt{2}) }{(n- \sqrt{2})(n- \sqrt{2}) } = \frac{ n^{2} }{n- \sqrt{2} } = \\ \\ \frac{(2 \sqrt{2} )}{2 \sqrt{2} - \sqrt{2} } = \frac{2 \sqrt{2} }{ \sqrt{2} } =2$

0 \\ \\ x \geq 0.1 \\ \\ 1-10x \leq 0 \\ x<0 \\ \\ x \geq 0.1 \\ x<0" alt="\frac{1-2x}{4x} -2 \leq 0 \\ \\ \frac{1-2x-8x}{4x} = \frac{1-10x}{4x} \leq 0 \\ \\ 1-10x \leq 0 \\ x>0 \\ \\ x \geq 0.1 \\ \\ 1-10x \leq 0 \\ x<0 \\ \\ x \geq 0.1 \\ x<0" align="absmiddle" class="latex-formula">
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Ответ: $x \geq 0.1$