1 \frac{x^3+2x^2-2x-1}{x^2-1}=\frac{(x-1)(x^2+3x+1)}{(x-1)(x+1)}=\frac{x^2+3x+1}{x+1}=\frac{5}{2}" alt="lim \ x->1 \frac{x^3+2x^2-2x-1}{x^2-1}=\frac{(x-1)(x^2+3x+1)}{(x-1)(x+1)}=\frac{x^2+3x+1}{x+1}=\frac{5}{2}" align="absmiddle" class="latex-formula">