[188-189] помогите Пожалуйста

$y^{2}-2y+3y-6-y^{2}+4y-4 \leq 6y-11 \\ 5y-10 \leq 6y-11 \\ -y \leq -1 \\ y \geq 1$

$y^{2}+3y-9y-27-y^{2}-8y-16 \geq 5-13y \\ -14y-43 \geq 5-13y \\ -y \geq 48 \\ y \leq -48$

-26" alt="9x^{2}+12x+4-16+24x-9x^{2}<37x+14 \\ 36x-12<37x+14 \\ -x<26 \\ x>-26" align="absmiddle" class="latex-formula">

16x^{2}-8x+1+9x^{2} \\ -20x-11>-8x+1 \\ -12x>12 \\ x<-1" alt="25x^{2}-20x+4-15>16x^{2}-8x+1+9x^{2} \\ -20x-11>-8x+1 \\ -12x>12 \\ x<-1" align="absmiddle" class="latex-formula">

$x^{2}-2xy+y^{2}+x^{2}+2xy+y^{2}=2(x^{2}+y^{2}) \\2x^{2}+2y^{2}=2(x^{2}+y^{2}) \\ 2(x^{2}+y^{2})=2(x^{2}+y^{2})$

$a^{2}-4ab+4b^{2}+4ab+4b^{2}=a^{2}+8b^{2} \\ a^{2}+8b^{2}=a^{2}+8b^{2}$

$36+12x^{2}+x^{4}-64+16x^{2}-x^{4}+28=28x^{2} \\ 28x^{2}=28x^{2}$

$16-40x^{3}+25x^6-25x^6+9=5(5-8x^{3}) \\25-40x^3=5(5-8x^{3}) \\ 5(5-8x^3)=5(5-8x^{3})$