помогите решить систему уровнений (x-y=2 (xy=3
X=y+2 y²+2y-3=0 y=1 x=3 y=-3 x=-1
(x-y=2 (xy=3 ( x= y+2 ( y(y+2) - 3 = 0 y^2 + 2y - 3 = 0 Δ = 4 + 4*3 = 12 + 4 = 16 y1 = ( - 2 +4)/2 = 1 y2 = ( - 2 - 4)/2 = - 3 ( x= 3 ( y = 1 ( x= -1 ( y = - 3