1)Решите уравнение (10x-3)+(12x-4)-7-(15-22x)

Question

1)Решите уравнение (10x-3)+(12x-4)-7-(15-22x)

Comments

10x-3=0, 10x=3, x=3/10=0.3; 12x-4=0, 12x=4, x=4/12=1/3, 15-22x=0, -22x=-15, x=15/20=5/4

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а потом 0.3+1/3-7-5/4

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сама дальше можешь?

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0.3+0.3-7-0.25=?

Answer 1

10х-3+12х-4=7-15+22x; 22х-7=-8+22х; 22x-22x=7-8

Comments

(10x-3)+(12x-4)=7-(15-22x)