{(x-y)(x+y)=12
{x+y=3(x-y)
3(x-y)^2=12
x-y= +-2
x=+-2 +y
x1 = 2+y
2(2+2y)=12
2+2y=6
1+y=3
y1=2
x2=-2+y
-2(-2+2y)=12
-2+2y=-6
-1+y=-3
y2=-2
Ответ x1=4, y1 = 2, x2=-4, y2=-2