Решите систему уравнений: (3х+7у)^2 =10y (3x+7y)^2=10x
(3x+7y)²=10y (3x+7y)²=10x 10x=10y (3x+7y)²=10x y=x (3x+7x)²=10x y=x (10x)²=10x y=x 100x²-10x=0 y=x 10x(10x-1)=0 x₁=0 y₁=0 x₂=1/10 y₁=1/10