Решите систему уравнений {X+Y=-2; X"2+Y"2=100
X + y = - 2 x^2 + y^2 = 100 x = - 2 - y ( - 2 - y)^2 + y^2 - 100 = 0 ** ** y^2 + 4y + 4 + y^2 - 100 = 0 2y^2 + 4y - 96 = 0 //:2 y^2 + 2y - 48 = 0 y = - 8 y = 6 y = 6 x = - 2 - 6 = - 8 y = - 8 x = - 2 + 8 = 6 ОТВЕТ: ( - 8; 6) ; ( 6 ; - 8)