Решить систему: (3x+7y)^2=10y (3x+7y)^2=10x
(3x+7y)^2=(3x+7y)^2 10x=10y x=y 100x^2=10x 10x^2-x=0 x(x-0.1)=0 x=0 x=0.1 y=0 y=0.1