y=(x - 1)² × (x - 4), [0;2]
y=(x² - 2x + 1) × (x - 4) = x³ - 4x² - 2x² + 8x + x - 4 = x³ - 6x² + 9x - 4
y'(x)= (x³ - 6x² + 9x - 4)' = 3x² - 12x + 9
y'(x) =0, 3x² - 12x + 9 = 0 |:3
x² - 4x + 3 = 0
D= 16 - 4*1*3 = 16 - 12 = 4
x₁= 4+2/2 = 3
х₂= 4 - 2/2 = 1
y(0)= (0 - 1)² × (0 - 4) = 1 × (-4)= -4
y(1) = (1 - 1)² × (1 - 4) = 0 × (-3) = 0
y(2) = (2 - 1)² × (2 - 4) = 1* (-2) = -2
у наиб. = 0
у наим. = -4.
