0 \\
x_{2} = \frac{-2+ \sqrt{36} }{2} =2 \\
x_{3} = \frac{-2- \sqrt{36} }{2} =-4 \\
" alt="(x-1)( x^{2} +6x+9)=5(x+3) \\
(x-1)(x+3)^2-5(x+3)=0 \\
((x-1)(x+3)-5)(x+3)=0 \\
( x^{2} +2x-8)(x+3)=0 \\
x+3=0 \\
x_{1} =-3 \\
x^{2} +2x-8=0 \\
D>0 \\
x_{2} = \frac{-2+ \sqrt{36} }{2} =2 \\
x_{3} = \frac{-2- \sqrt{36} }{2} =-4 \\
" align="absmiddle" class="latex-formula">