0 \ \Rightarrow \ a^n < b^n\\\\
\frac{2}{9} < \frac{1}{4}, \ \frac{2}{9} \geq 0, \ \frac{3}{5} > 0 \ \Rightarrow \ \frac{2}{9}^\frac{3}{5} < \frac{1}{4}^\frac{3}{5}\\\\
\sqrt[5]{(\frac{2}{9})^3} < \sqrt[5]{(\frac{1}{4})^3}" alt="\frac{2}{9} = \frac{2*4}{9*4} = \frac{8}{36} < \frac{9}{36} = \frac{1*9}{4*9} = \frac{1}{4}\\\\
a < b, \ a \geq 0, \ n > 0 \ \Rightarrow \ a^n < b^n\\\\
\frac{2}{9} < \frac{1}{4}, \ \frac{2}{9} \geq 0, \ \frac{3}{5} > 0 \ \Rightarrow \ \frac{2}{9}^\frac{3}{5} < \frac{1}{4}^\frac{3}{5}\\\\
\sqrt[5]{(\frac{2}{9})^3} < \sqrt[5]{(\frac{1}{4})^3}" align="absmiddle" class="latex-formula">