X=π/4+πn, n∈Z [5π;13π/2]= [5π; 6,5π]
n=0 x1=π/4+0π=π/4∉ [5π; 6,5π]
n=1 x2=π/4+π=5π/4∉ [5π; 6,5π]
n=2 x3=π/4+2π=9π/4∉ [5π; 6,5π]
n=3 x4=π/4+3π=13π/4∉ [5π; 6,5π]
n=4 x5=π/4+4π=17π/4∉ [5π; 6,5π]
n=5 x6=π/4+5π=21π/4∈[5π; 6,5π]
n=6 x7=π/4+7π=25π/4∈ [5π; 6,5π]
n=7 x8=π/4+8π=33π/4∉ [5π; 6,5π]
Ответ: 21π/4; 25π/4