12-(4-x)^2=x(3-x) помгите

Question

12-(4-x)^2=x(3-x) помгите

Answer 1

12-(4-x)^2=x(3-x)
12-(16-8x+x^2) = 3x-x^2
12-16+8x-x^2-3x+x^2=0
5x-4=0
5x=4
x=4/5
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