1)3x/(x³-1) -5/(4x²+4x+4) - 1/2(1-x)=3x/(x-1)(x²+x+1)- 5/4(x²+x_1)+1/2(x-1)=0
x-1≠0⇒x≠1
x²+x+1>0при любом х
12x-5x+5+2x²+2x+2=0
2x²+9x+7=0
D=81-56=25
x1=(-9-5)/4=-3,5
x2=(-9+5)/4=-1
2)(x-2)(2x-1)/(2x²+7x+3)>0
x-2=0⇒x=2
2x-1=0⇒x=1/2
2x²+7x+3=0
D=49-24=25
x=(-7-5)/4=-3
x=(-7+5)/4=-1/2
+ _ + _ +
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-3 -1/2 1/2 2
x∈(-∞;-3) U (-1/2;1/2) U (2;∞)
3)(x-3)(2-x)/(3+x)(x+2)<-1<br>(x-3)(2-x)/(3+x)(x+2)+1<0<br>(2x-x²-6+3x+3x+6+x²+2x)/(3+x)(x+2)<0<br>10x/(3+x)(x+2)<0<br>x=0
3+x=0⇒x=-3
x+2=0⇒x=-2
_ + _ +
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-3 -2 0
x∈(-∞;-3) U (-2;0)