0} \atop {4x+1>0}} \right. \; \left \{ {{x>5} \atop {x>-\frac{1}{4}}} \right. \; x>5\\\\x-5=4x+1\\\\3x=-6\\\\x=-2\notin OOF\\\\Otvet:net\; reshenij" alt="log_2(x-5)=log_2(4x+1),\; \; OOF:\; \left \{ {{x-5>0} \atop {4x+1>0}} \right. \; \left \{ {{x>5} \atop {x>-\frac{1}{4}}} \right. \; x>5\\\\x-5=4x+1\\\\3x=-6\\\\x=-2\notin OOF\\\\Otvet:net\; reshenij" align="absmiddle" class="latex-formula">