РЕШИТЬ !ПО ДЕЙСТВИЯМ! (3 целых 1/2 - 7/9) • 6/11+(8/33-1/11):10/11= ?

Решите задачу:

$(3 \frac{1}{2} - \frac{7}{9} ) * \frac{6}{11} +( \frac{8}{33}- \frac{1}{11}): \frac{10}{11} \\ 1)\,3 \frac{1}{2} - \frac{7}{9}= \frac{7}{2} - \frac{7}{9}= \frac{7*9-7*2}{18}= \frac{63-14}{18} = \frac{49}{18} \\ 2)\, \frac{8}{33}- \frac{1}{11}= \frac{8-1*3}{33} = \frac{5}{33} \\ 3)\, \frac{49}{18} * \frac{6}{11} = \frac{49*6}{18*11} = \frac{49}{3*11} =\frac{49}{33} \\ 4)\, \frac{5}{33} : \frac{10}{11} =\frac{4}{33}* \frac{11}{10}=\frac{5*11}{33*10}=\frac{1}{3*2}=\frac{1}{6} \\$
$5)\, \frac{49}{33} + \frac{1}{6} = \frac{49}{3*11} + \frac{1}{3*2} = \frac{49*2+1*11}{3*2*11} = \frac{109}{3*2*11} = \frac{109}{66} =1\frac{43}{66}$